Check if array contains specific value

Question

I have this array, with some values (int) and I want to check if a value given by the user is equal to a value in that string. If it is, output a message like "Got your string".

Example of the list:

local op = {
{19},
{18},
{17}
}

if 13 == (the values from that array) then
  message
else
  other message

How can this be done?

Answer 1

Lua doesn't have strict arrays like other languages - it only has hash tables. Tables in Lua are considered array-like when their indices are numerical and densely packed, leaving no gaps. The indices in the following table would be 1, 2, 3, 4.

local t = {'a', 'b', 'c', 'd'}

When you have an array-like table, you can check if it contains a certain value by looping through the table. You can use a for..in loop, and the ipairs function to create a generic function.

local function has_value (tab, val)
    for index, value in ipairs(tab) do
        if value == val then
            return true
        end
    end

    return false
end

We can use the above in an if conditional to get our result.

if has_value(arr, 'b') then
    print 'Yep'
else
    print 'Nope'
end

To reiterate my comment above, your current example code is not an array-like table of numbers. Instead it is an array-like table containing array-like tables, who have numbers in each of their first indices. You'd need to modify the function above to work with your shown code, making it less generic.

local function has_value (tab, val)
    for index, value in ipairs(tab) do
        -- We grab the first index of our sub-table instead
        if value[1] == val then
            return true
        end
    end

    return false
end

Lua is not a very large or complex language, and its syntax is very clearcut. If the above concepts are totally alien to you, you'll need to spend some time reading real literature, not just copying examples. I would advise reading Programming in Lua to make sure you understand the very basics. This is the first edition, aimed at Lua 5.1.