Batch-Script - Iterate through arguments

Question

I have a batch-script with multiple arguments. I am reading the total count of them and then run a for loop like this:

@echo off
setlocal enabledelayedexpansion

set argCount=0
for %%x in (%*) do set /A argCount+=1
echo Number of processed arguments: %argCount%

set /a counter=0
for /l %%x in (1, 1, %argCount%) do (
set /a counter=!counter!+1 )

What I want to do now, is to use my running variable (x or counter) to access the input arguments. I am thinking aobut something like this:

REM Access to %1 
echo %(!counter!)

In an ideal world this line should print out my first command line argument but obviously it doesn't. I know I am doing something wrong with the % operator, but is there anyway I could access my arguments like this?

//edit: Just to make things clear - the problem is that %(!counter!) provides me with the value of the variable counter. Meaning for counter=2 it gives me 2 and not the content of %2.

Answer 1

@echo off
setlocal enabledelayedexpansion

set argCount=0
for %%x in (%*) do (
   set /A argCount+=1
   set "argVec[!argCount!]=%%~x"
)

echo Number of processed arguments: %argCount%

for /L %%i in (1,1,%argCount%) do echo %%i- "!argVec[%%i]!"

For example:

C:> test One "This is | the & second one" Third
Number of processed arguments: 3
1- "One"
2- "This is | the & second one"
3- "Third"

Another one:

C:> test One Two Three Four Five Six Seven Eight Nine Ten Eleven Twelve etc...
Number of processed arguments: 13
1- "One"
2- "Two"
3- "Three"
4- "Four"
5- "Five"
6- "Six"
7- "Seven"
8- "Eight"
9- "Nine"
10- "Ten"
11- "Eleven"
12- "Twelve"
13- "etc..."