The `long long` size modifier was introduced in C++11 and can be used with integral types to select an integer of at least 64 bits.
I am trying to find the square of a int. My code looks like below: long long sqr=0; int num=77778; …
c++ multiplication integer-overflow long-long#include <stdio.h> int main(void) { long long x = test(); printf("%lld\n", x); return 1; } long long test() { …
c++ c visual-c++ long-long