Say you want to convert a matrix to a list, where each element of the list contains one column. list()
or as.list()
obviously won't work, and until now I use a hack using the behaviour of tapply
:
x <- matrix(1:10,ncol=2)
tapply(x,rep(1:ncol(x),each=nrow(x)),function(i)i)
I'm not completely happy with this. Anybody knows a cleaner method I'm overlooking?
(for making a list filled with the rows, the code can obviously be changed to :
tapply(x,rep(1:nrow(x),ncol(x)),function(i)i)
)
Gavin's answer is simple and elegant. But if there are many columns, a much faster solution would be:
lapply(seq_len(ncol(x)), function(i) x[,i])
The speed difference is 6x in the example below:
> x <- matrix(1:1e6, 10)
> system.time( as.list(data.frame(x)) )
user system elapsed
1.24 0.00 1.22
> system.time( lapply(seq_len(ncol(x)), function(i) x[,i]) )
user system elapsed
0.2 0.0 0.2