jpegtran optimize without changing filename

linux image image-processing image-manipulation
David picture David · Apr 7, 2011 · Viewed 23.1k times · Source

I need to optimize some images, but not change their name. 

jpegtran -copy none -optimize image.jpg > image.jpg

However, this seems to create an filesize of 0. When i do it to a different filename, the size is still exactly the same.

Answer

so12311 picture so12311 · Apr 7, 2011

how about:

jpegtran -copy none -optimize -outfile image.jpg image.jpg

I'm not a shell expert by any means, but I think that with your original command, as soon as it is executed, the redirect is set up which overwrites your image.jpg. Then when jpegtran tries to read it in it finds an empty file.

Related questions

How to base64 encode image in linux bash / shell

I'm trying to base64 encode an image in a shell script and put it into variable: test="$(printf DSC_0251.JPG | base64)" echo $test RFNDXzAyNTEuSlBH I've also tried something like this: test=\`echo -ne DSC_0251.JPG | base64\` but still with no …

Read More
Fast way to get image dimensions (not filesize)

I'm looking for a fast way to get the height and width of an image in pixels. It should handle at least JPG, PNG and TIFF, but the more the better. I emphasize fast because my images are quite big (…

Read More
How to create an .IMG image of a disc (sd card) without including free space?

In Linux, we can do dd if=/dev/sdb of=bckup.img but if the disk is of 32GB with only 4GB used, the 32GB image file is waste of space-time. Is there any way or tool to create images …

Read More