I know this could be easy, but I am unable to figure out. We want to run two instances of luigi on one machine so need to modify init.d script to write PID to file rather than just touching empty file.
echo -n $"Starting luigid scheduler as $LUIGID_USER: "
( ( /usr/bin/sudo -u $LUIGID_USER $LUIGID_BIN >>/var/log/luigid/server.log 2>&1 ) &)
RETVAL=$?
[ $RETVAL -eq 0 ] && touch /var/lock/subsys/luigid && echo_success || echo_failure
echo
return $RETVAL
At present its just touching the empty PID file. I want it to write PID into the file. Also while stopping I want to kill by PID stored in PID file
echo -n $"Stopping luigid scheduler: "
killproc luigid
RETVAL=$?
[ $RETVAL -eq 0 ] && rm -f /var/lock/subsys/luigid && echo_success || echo_failure
echo
Any help please ?
Thanks
You can get the PID
of the previous command with $!
Change the start script to:
echo -n "Starting luigid scheduler as $LUIGID_USER: "
/usr/bin/sudo -u $LUIGID_USER $LUIGID_BIN >>/var/log/luigid/server.log 2>&1 &
RETVAL=$?
PID=$!
[ $RETVAL -eq 0 ] && echo $PID > /var/lock/subsys/luigid && echo_success || echo_failure
echo
return $RETVAL
Note you need to remove the brackets from around the command as they start the program in a subshell. The subshell will not return the PID of the started program back to your shell, so you should call it directly from your shell.