Command to zip a directory using a specific directory as the root

linux command-line zip command
Tarka picture Tarka · Mar 18, 2010 · Viewed 38k times · Source

I'm writing a PHP script that downloads a series of generated files (using wget) into a directory, and then zips then up, using the zip command.

The downloads work perfectly, and the zipping mostly works. I run the command:

zip -r /var/www/oraviewer/rgn_download/download/fcst_20100318_0319.zip /var/www/oraviewer/rgn_download/download/fcst_20100318_0319

which yields a zip file with all the downloaded files, but it contains the full /var/www/oraviewer/rgn_download/download/ directories, before reaching the fcst_20100318_0319/ directory.

I'm probably just missing a flag, or something small, from the zip command, but how do I get it to use fcst_20100318_0319/ as the root directory?

Answer

JayM picture JayM · Mar 18, 2010

I don't think zip has a flag to do that. I think the only way is something like:

cd /var/www/oraviewer/rgn_download/download/ && \
   zip -r fcst_20100318_0319.zip fcst_20100318_0319

(The backslash is just for clarity, you can remove it and put everything on one line.)

Since PHP is executing the command in a subshell, it won't change your current directory.

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