How to force 'cp' to overwrite directory instead of creating another one inside?

Question

I'm trying to write a Bash script that will overwrite an existing directory. I have a directory foo/ and I am trying to overwrite bar/ with it. But when I do this:

cp -Rf foo/ bar/

a new bar/foo/ directory is created. I don't want that. There are two files in foo/; a and b. There are files with same names in bar/ as well. I want the foo/a and foo/b to replace bar/a and bar/b.

Answer 1

You can do this using -T option in cp.
See Man page for cp.

-T, --no-target-directory
    treat DEST as a normal file

So as per your example, following is the file structure.

$ tree test
test
|-- bar
|   |-- a
|   `-- b
`-- foo
    |-- a
    `-- b
2 directories, 4 files

You can see the clear difference when you use -v for Verbose.
When you use just -R option.

$ cp -Rv foo/ bar/
`foo/' -> `bar/foo'
`foo/b' -> `bar/foo/b'
`foo/a' -> `bar/foo/a'
 $ tree
 |-- bar
 |   |-- a
 |   |-- b
 |   `-- foo
 |       |-- a
 |       `-- b
 `-- foo
     |-- a
     `-- b
3 directories, 6 files

When you use the option -T it overwrites the contents, treating the destination like a normal file and not directory.

$ cp -TRv foo/ bar/
`foo/b' -> `bar/b'
`foo/a' -> `bar/a'

$ tree
|-- bar
|   |-- a
|   `-- b
`-- foo
    |-- a
    `-- b
2 directories, 4 files

This should solve your problem.