Linux - How to list all users

linux awk grep uid
Tadeusz Majkowski picture Tadeusz Majkowski · Nov 28, 2013 · Viewed 52.7k times · Source

How to write a script for linux which list all users from /etc/passwd and their UID

User1 uid=0001
User2 uid=0002
...

the script should use: grep, cut, id, for

Answer

Kent picture Kent · Nov 28, 2013 
awk -F: '$0=$1 " uid="$3' /etc/passwd

awk is easier in this case.

-F defines field separator as :

so you want is 1st and 3rd colums. so build the $0 to provide your output format.

this is very basic usage of powerful awk. you may want to read some tutorials if you faced this kind of problem often.

This time you got fish, if I were you, I am gonna do some research on how to fishing.

Related questions

What are the differences among grep, awk & sed?

Possible Duplicate: What are the differences between Perl, Python, AWK and sed? What is the difference between sed and awk? Maybe not a very specific question, but I am confused about the differences between grep, awk and sed in terms …

Read More
Command line: search and replace in all filenames matched by grep

I'm trying to search and replace a string in all files matched by grep: grep -n 'foo' * will give me output in the form: [filename]:[line number]:[text] For each file returned by grep, I'd like to modify the file …

Read More
grep for text with wild card in between

I would like to grep something like ==> *.sh <==. But it doesn't work, I can grep everything up to .sh <== but not get the wild card to work. What's the trick here?

Read More