i tried to install
1.yum install -zxvf apache-tomcat-6.0.47.tar.gz then
2. export TOMCAT_HOME=/home/mpatil/softwares/apache-tomcat-6.0.37
3. [root@localhost mpatil]# echo $TOMCAT_HOME
/home/mpatil/softwares/apache-tomcat-7.0.47
while starting tomcat by using this command
4.[root@localhost mpatil]# /startup.sh
bash: /startup.sh: No such file or directory
i don't know why it showing like this.
my file in
5.[root@localhost mpatil]# find /home -type f -name apache-tomcat-6.0.37.tar.gz
/home/mpatil/Downloads/apache-tomcat-6.0.37.tar.gz
what i tried before this is is correct or not? --please tell me my question is how to start a tomcat server in linux.Please tell me..
The command you have typed is /startup.sh
, if you have to start a shell script you have to fire the command as shown below:
$ cd /home/mpatil/softwares/apache-tomcat-7.0.47/bin
$ sh startup.sh
or
$ ./startup.sh
Please try that, you also have to go to your tomcat's bin-folder (by using the cd-command) to execute this shell script. In your case this is /home/mpatil/softwares/apache-tomcat-7.0.47/bin
.