How to pass argument in Expect through the command line in a shell script

linux bash shell expect
lk121 picture lk121 · Jun 12, 2013 · Viewed 97k times · Source

I am passing argument in Expect through the command line in a shell script.

I tried this

#!/usr/bin/expect -f
    
set arg1 [lindex $argv 0]
    
spawn lockdis -p
expect "password:" {send "$arg1\r"}
expect "password:" {send "$arg1\r"}
expect "$ "

But it's not working. How can I fix it?

Answer

bartimar picture bartimar · Jun 12, 2013

If you want to read from arguments, you can achieve this simply by

set username [lindex $argv 0];
set password [lindex $argv 1];

And print it

send_user "$username $password"

That script will print

$ ./test.exp user1 pass1
user1 pass1

You can use Debug mode

$ ./test.exp -d user1 pass1

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