Unix cut except last two tokens

linux bash unix token cut
user613114 picture user613114 · Dec 23, 2012 · Viewed 15k times · Source

I'm trying to parse file names in specific directory. Filenames are of format:

token1_token2_token3_token(N-1)_token(N).sh

I need to cut the tokens using delimiter '_', and need to take string except the last two tokens. In above examlpe output should be token1_token2_token3.

The number of tokens is not fixed. I've tried to do it with -f#- option of cut command, but did not find any solution. Any ideas?

Answer

ysth picture ysth · Dec 23, 2012

With cut:

$ echo t1_t2_t3_tn1_tn2.sh | rev | cut -d_ -f3- | rev
t1_t2_t3

rev reverses each line. The 3- in -f3- means from the 3rd field to the end of the line (which is the beginning of the line through the third-to-last field in the unreversed text).

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