Sort files numerically in bash

Question

I need to sort .flv files numerically and i was able to do it with the following command:

ls *\.flv | sort --version-sort -f

but with many files(hundreds) it's not sorting correctly.

ls *\.flv | sort --version-sort -f | tail -n 20
e680.flv
e681.flv
e682.flv
e683.flv
e684.flv
e685.flv
e686.flv
e687.flv
e688.flv
e689.flv
e690.flv
e691.flv
e692.flv
e693.flv
e694.flv
e695.flv
**e696.flv**
s572.flv
s602.flv
s654.flv

but the strange this is, if i'm ruining the command without "*.flv" it's working. i could use just ls but i have other file types in the folder.

ls | sort --version-sort -f | tail -n 20
e680.flv
e681.flv
e682.flv
e683.flv
e684.flv
e685.flv
e686.flv
e687.flv
e688.flv
e689.flv
e690.flv
e691.flv
e692.flv
e693.flv
e694.flv
e695.flv
e696.flv

what i've tried so far:

    ls | sort --version-sort -f | grep "flv"
    ls *.flv | sort --version-sort -f
    ls *\.flv | sort --version-sort -f
    ls *.flv | sort -f

Answer 1

I would try following code. Works on my testing scenario:

ls -1 *\.flv | sort -n -k1.2

The ls lists flv files 1 on each line, sort takes first (and only one) word on each line starting on second character (start of the number). Sorts numerically