Run shell script for every file in directory

general exception picture general exception · Apr 21, 2012 · Viewed 7k times · Source

I have a bunch of files in a directory all named YYYY_MM_DD

-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_05
-rw-r--r-- 1 root root 483K Apr 21 13:17 2012_04_06
-rw-r--r-- 1 root root 484K Apr 21 13:17 2012_04_07
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_08
-rw-r--r-- 1 root root 344K Apr 21 13:17 2012_04_09
-rw-r--r-- 1 root root  66K Apr 21 13:17 2012_04_10
-rw-r--r-- 1 root root 461K Apr 21 13:17 2012_04_11
-rw-r--r-- 1 root root 475K Apr 21 15:09 2012_04_17
-rw-r--r-- 1 root root 480K Apr 21 15:10 2012_04_18
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_19
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_20

I have a shell script that accepts a file as a paramater and calculates figures based on the data in the file, i call the script like this

sh Calculate.sh MyFile

I want to run this shell script for every file in this directory.

How would i go about doing this, xargs ??

Answer

MrJames picture MrJames · Apr 21, 2012

Have you tried the find command with execution ?

My sample will echo the files, but you can call a shell script with the filename as a parameter

find . -maxdepth 1 -type f -exec echo {} \;