Im working on an assignment and im currently stuck. This is part of the question:
Accepts exactly 7 characters and echoes them to the console. Moves on to the next line after 7 characters without waiting for return/enter.
So ive made a loop which loops 7 times, gets input and displays on the screen and also stores the characters (i think). But i am unable to print the saved string on the next line.
LEA R2, memorySpace ; allocates memory to R2 for string storage
LD R1, upiLoop ; condition for loop (loops 7 times)
loop
GETC
PUTC
STR R0, R2, #0 ; r0 -> ( memory address stored in r2 + 0 )
ADD R2, R2, #1 ; increments the memory pointer
ADD R1, R1, #-1 ; decrements loop
BRz loop
upiLoop .FILL 7
memorySpace .blkw 100 ; empty space to store string
All i can do is just see the characters which i type in.. I want to print the characters on the next line as 1 string.
So far you've taken in characters and made a string. Now you just need to print the string. You do this by supplying R0 with the starting address of the string and calling the PUTS trap. Note that the last character of the string will need to be NULL. So, after the loop:
LEA R0, memorySpace
PUTS