I'm new to Lumen and want to create an app with this framework. Now I have the problem that if some user enters a wrong url => http://www.example.com/abuot (wrong) => http://www.example.com/about (right), I want to present a custom error page and it would be ideal happen within the middleware level.
Furthermore, I am able to check if the current url is valid or not, but I am not sure how can I "make" the view within the middleware, the response()->view() won't work.
Would be awesome if somebody can help.
Answer
Seeing as errors are handled in App\Exceptions\Handler, this is the best place to deal with them.
If you are only after a custom 404 error page, then you could do this quite easily:
Add this line up the top of the Handler file:
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
Alter the render function to look like so:
public function render($request, Exception $e)
{
if($e instanceof NotFoundHttpException){
return response(view("errors.404"), 404);
}
return parent::render($request, $e);
}
This assumes your custom 404 page is stored in an errors folder within your views, and will return the custom error page along with a 404 status code.