I built a Sequential model with the VGG16 network at the initial base, for example:
from keras.applications import VGG16
conv_base = VGG16(weights='imagenet',
# do not include the top, fully-connected Dense layers
include_top=False,
input_shape=(150, 150, 3))
from keras import models
from keras import layers
model = models.Sequential()
model.add(conv_base)
model.add(layers.Flatten())
model.add(layers.Dense(256, activation='relu'))
# the 3 corresponds to the three output classes
model.add(layers.Dense(3, activation='sigmoid'))
My model looks like this:
model.summary()
Layer (type) Output Shape Param # ================================================================= vgg16 (Model) (None, 4, 4, 512) 14714688 _________________________________________________________________ flatten_1 (Flatten) (None, 8192) 0 _________________________________________________________________ dense_7 (Dense) (None, 256) 2097408 _________________________________________________________________ dense_8 (Dense) (None, 3) 771 ================================================================= Total params: 16,812,867 Trainable params: 16,812,867 Non-trainable params: 0 _________________________________________________________________
Now, I want to get the layer names associated with the vgg16 Model portion of my network. I.e. something like:
layer_name = 'block3_conv1'
filter_index = 0
layer_output = model.get_layer(layer_name).output
loss = K.mean(layer_output[:, :, :, filter_index])
However, since the vgg16 convolutional is shown as a Model and it's layers are not being exposed, I get the error:
ValueError: No such layer: block3_conv1
How do I do this?
The key is to first do .get_layer
on the Model object, then do another .get_layer
on that specifying the specific vgg16 layer, THEN do .output:
layer_output = model.get_layer('vgg16').get_layer('block3_conv1').output