I'm trying to fetch a JSON response and store the results in a variable. I've had versions of this code work in previous releases of Swift, until the GM version of Xcode 8 was released. I had a look at a few similar posts on StackOverflow: Swift 2 Parsing JSON - Cannot subscript a value of type 'AnyObject' and JSON Parsing in Swift 3.
However, it seems the ideas conveyed there do not apply in this scenario.
How do I correctly parse the JSON reponse in Swift 3? Has something changed in the way JSON is read in Swift 3?
Below is the code in question (it can be run in a playground):
import Cocoa
let url = "https://api.forecast.io/forecast/apiKey/37.5673776,122.048951"
if let url = NSURL(string: url) {
if let data = try? Data(contentsOf: url as URL) {
do {
let parsedData = try JSONSerialization.jsonObject(with: data as Data, options: .allowFragments)
//Store response in NSDictionary for easy access
let dict = parsedData as? NSDictionary
let currentConditions = "\(dict!["currently"]!)"
//This produces an error, Type 'Any' has no subscript members
let currentTemperatureF = ("\(dict!["currently"]!["temperature"]!!)" as NSString).doubleValue
//Display all current conditions from API
print(currentConditions)
//Output the current temperature in Fahrenheit
print(currentTemperatureF)
}
//else throw an error detailing what went wrong
catch let error as NSError {
print("Details of JSON parsing error:\n \(error)")
}
}
}
Edit: Here is a sample of the results from the API call after print(currentConditions)
["icon": partly-cloudy-night, "precipProbability": 0, "pressure": 1015.39, "humidity": 0.75, "precipIntensity": 0, "windSpeed": 6.04, "summary": Partly Cloudy, "ozone": 321.13, "temperature": 49.45, "dewPoint": 41.75, "apparentTemperature": 47, "windBearing": 332, "cloudCover": 0.28, "time": 1480846460]
First of all never load data synchronously from a remote URL, use always asynchronous methods like URLSession
.
'Any' has no subscript members
occurs because the compiler has no idea of what type the intermediate objects are (for example currently
in ["currently"]!["temperature"]
) and since you are using Foundation collection types like NSDictionary
the compiler has no idea at all about the type.
Additionally in Swift 3 it's required to inform the compiler about the type of all subscripted objects.
You have to cast the result of the JSON serialization to the actual type.
This code uses URLSession
and exclusively Swift native types
let urlString = "https://api.forecast.io/forecast/apiKey/37.5673776,122.048951"
let url = URL(string: urlString)
URLSession.shared.dataTask(with:url!) { (data, response, error) in
if error != nil {
print(error)
} else {
do {
let parsedData = try JSONSerialization.jsonObject(with: data!) as! [String:Any]
let currentConditions = parsedData["currently"] as! [String:Any]
print(currentConditions)
let currentTemperatureF = currentConditions["temperature"] as! Double
print(currentTemperatureF)
} catch let error as NSError {
print(error)
}
}
}.resume()
To print all key / value pairs of currentConditions
you could write
let currentConditions = parsedData["currently"] as! [String:Any]
for (key, value) in currentConditions {
print("\(key) - \(value) ")
}
A note regarding jsonObject(with data
:
Many (it seems all) tutorials suggest .mutableContainers
or .mutableLeaves
options which is completely nonsense in Swift. The two options are legacy Objective-C options to assign the result to NSMutable...
objects. In Swift any var
iable is mutable by default and passing any of those options and assigning the result to a let
constant has no effect at all. Further most of the implementations are never mutating the deserialized JSON anyway.
The only (rare) option which is useful in Swift is .allowFragments
which is required if if the JSON root object could be a value type(String
, Number
, Bool
or null
) rather than one of the collection types (array
or dictionary
). But normally omit the options
parameter which means No options.
===========================================================================
JSON is a well-arranged text format. It's very easy to read a JSON string. Read the string carefully. There are only six different types – two collection types and four value types.
The collection types are
[]
- Swift: [Any]
but in most cases [[String:Any]]
{}
- Swift: [String:Any]
The value types are
"Foo"
, even "123"
or "false"
– Swift: String
123
or 123.0
– Swift: Int
or Double
true
or false
not in double quotes – Swift: true
or false
null
– Swift: NSNull
According to the JSON specification all keys in dictionaries are required to be String
.
Basically it's always recommeded to use optional bindings to unwrap optionals safely
If the root object is a dictionary ({}
) cast the type to [String:Any]
if let parsedData = try JSONSerialization.jsonObject(with: data!) as? [String:Any] { ...
and retrieve values by keys with (OneOfSupportedJSONTypes
is either JSON collection or value type as described above.)
if let foo = parsedData["foo"] as? OneOfSupportedJSONTypes {
print(foo)
}
If the root object is an array ([]
) cast the type to [[String:Any]]
if let parsedData = try JSONSerialization.jsonObject(with: data!) as? [[String:Any]] { ...
and iterate through the array with
for item in parsedData {
print(item)
}
If you need an item at specific index check also if the index exists
if let parsedData = try JSONSerialization.jsonObject(with: data!) as? [[String:Any]], parsedData.count > 2,
let item = parsedData[2] as? OneOfSupportedJSONTypes {
print(item)
}
}
In the rare case that the JSON is simply one of the value types – rather than a collection type – you have to pass the .allowFragments
option and cast the result to the appropriate value type for example
if let parsedData = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? String { ...
Apple has published a comprehensive article in the Swift Blog: Working with JSON in Swift
===========================================================================
Codable
protocol provides a more convenient way to parse JSON directly into structs / classes.For example the given JSON sample in the question (slightly modified)
let jsonString = """
{"icon": "partly-cloudy-night", "precipProbability": 0, "pressure": 1015.39, "humidity": 0.75, "precip_intensity": 0, "wind_speed": 6.04, "summary": "Partly Cloudy", "ozone": 321.13, "temperature": 49.45, "dew_point": 41.75, "apparent_temperature": 47, "wind_bearing": 332, "cloud_cover": 0.28, "time": 1480846460}
"""
can be decoded into the struct Weather
. The Swift types are the same as described above. There are a few additional options:
URL
can be decoded directly as URL
. time
integer can be decoded as Date
with the dateDecodingStrategy
.secondsSince1970
.keyDecodingStrategy
.convertFromSnakeCase
struct Weather: Decodable {
let icon, summary: String
let pressure: Double, humidity, windSpeed : Double
let ozone, temperature, dewPoint, cloudCover: Double
let precipProbability, precipIntensity, apparentTemperature, windBearing : Int
let time: Date
}
let data = Data(jsonString.utf8)
do {
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .secondsSince1970
decoder.keyDecodingStrategy = .convertFromSnakeCase
let result = try decoder.decode(Weather.self, from: data)
print(result)
} catch {
print(error)
}
Other Codable sources: