Convert to time in Golang from milliseconds

sadlil picture sadlil · Jul 31, 2015 · Viewed 20.9k times · Source

I have a some json data where there is a field called lastModifed contains time in millis. I wanted to convert this data into a struct type with json.UnMarshaller. I have mapped the field with json filed. But the conversion seems not working.

IE :

My Json looks like this:

{
   "name" : "hello",
   "lastModified" : 1438167001716
}

and struct Looks like

type Model struct {
    Name         string    `json:"name"`
    Lastmodified time.Time `json:"lastModified"`
}

looks not converting the time properly. how can i get the time from those millis??

NB: The millis of lastModifiedTime are getting from java System.currentTimeMillis();

Answer

RoninDev picture RoninDev · Jul 31, 2015

In golang time.Time marshals to JSON using RFC3339, string representation. So you need to unmarshal your json using int64 instead of time.Time and convert after it by yourself:

type Model struct {
    Name   string `json:"name"`
    Millis int64  `json:"lastModified"`
}

func (m Model) Lastmodified() time.Time {
    return time.Unix(0, m.Millis * int64(time.Millisecond))
}

Go playground

Also you can use special wrapper above time.Time and override UnmarshalJSON there:

type Model struct {
    Name         string   `json:"name"`
    Lastmodified javaTime `json:"lastModified"`
}

type javaTime time.Time

func (j *javaTime) UnmarshalJSON(data []byte) error {
    millis, err := strconv.ParseInt(string(data), 10, 64)
    if err != nil {
        return err
    }
    *j = javaTime(time.Unix(0, millis * int64(time.Millisecond)))
    return nil
}

Go playground