filtering data based on a custom data attribute using jquery

zSynopsis picture zSynopsis · Jan 23, 2012 · Viewed 14.7k times · Source

I was wondering if someone could help with with some jquery code for doing the following. I have a drop down select list input that i would like to filter a list of checkboxes.

Here's what my html code looks like

 <span style="float:right;">

        <label>Filter</label> 
    <select id="office-type-list" name="OfficeTypes"><option value="00">All</option>

        <option value="05">Township</option>

        <option value="10">Municipality</option>

        <option value="15">Elementary School</option>

        <option value="20">High School</option>

    </select> 

</span>

<!-- List below -->

<div name="Offices">
    <div data-custom-type="00">
        <input type="checkbox" name="Offices" id="Offices_0000" value="0000" /> <label for="Offices_0000">All</label>
    </div>
    <div data-custom-type="05">
        <input type="checkbox" name="Offices" id="Offices_0010" value="0010" /> <label for="Offices_0010">Township 1p</label>
    </div>
    <div data-custom-type="05">
        <input type="checkbox" name="Offices" id="Offices_0020" value="0020" /> <label for="Offices_0020">Township 2</label>
    </div>
</div>

So if Township is selected (05) then only the divs with the data-custom-type="05" will display.

Is there a way to achieve this and if so some help would be much appreciated

Answer

Fr&#233;d&#233;ric Hamidi picture Frédéric Hamidi · Jan 23, 2012

You could do something like:

$("#office-type-list").change(function() {
    var customType = $(this).val();
    $("div[name=Offices]").children("div").hide().filter(function() {
        return $(this).data("custom-type") == customType;
    }).show();
});

The code above handles the change event of your <select> element by matching the <div> elements that are direct children of your main Offices element, hiding them all, then applying filter() to obtain the children whose data-custom-type attributes match the selected value, and showing these.