How to show loading spinner in jQuery?

Edward Tanguay picture Edward Tanguay · Sep 16, 2008 · Viewed 826.9k times · Source

In Prototype I can show a "loading..." image with this code:

var myAjax = new Ajax.Request( url, {method: 'get', parameters: pars, 
onLoading: showLoad, onComplete: showResponse} );

function showLoad () {
    ...
}

In jQuery, I can load a server page into an element with this:

$('#message').load('index.php?pg=ajaxFlashcard');

but how do I attach a loading spinner to this command as I did in Prototype?

Answer

nickf picture nickf · Sep 16, 2008

There are a couple of ways. My preferred way is to attach a function to the ajaxStart/Stop events on the element itself.

$('#loadingDiv')
    .hide()  // Hide it initially
    .ajaxStart(function() {
        $(this).show();
    })
    .ajaxStop(function() {
        $(this).hide();
    })
;

The ajaxStart/Stop functions will fire whenever you do any Ajax calls.

Update: As of jQuery 1.8, the documentation states that .ajaxStart/Stop should only be attached to document. This would transform the above snippet to:

var $loading = $('#loadingDiv').hide();
$(document)
  .ajaxStart(function () {
    $loading.show();
  })
  .ajaxStop(function () {
    $loading.hide();
  });