jQuery Ajax wait until all images are loaded

robs picture robs · Jan 23, 2011 · Viewed 38.1k times · Source

I'm trying to perform an Ajax call with jQuery which is working well. I use the success event to display the data. It seems however that success gets triggered as soon as the external HTML file gets loaded. If there are large images they keep loading after they're shown. Is there a way to display the content after everything is fully loaded? Here is the code:

$('#divajax').html('<br><div style="text-align: center;"><img src="res/ajax-loader.gif"></div>');
$.ajax({
    cache: false,
    url: 'ajax/content.php',
    success: function(data) {
          $('#divajax').html(data);
    }
});

Answer

Daniel Howard picture Daniel Howard · Aug 1, 2013

The plugin that @alex wrote didn't work for me for some reason... I couldn't figure out why. But his code did inspire me to come up with a more lightweight solution that is working for me. It uses jquery promises. Please note that unlike @alex 's plugin, this doesn't attempt to account for background images on elements, only img elements.

// Fn to allow an event to fire after all images are loaded
$.fn.imagesLoaded = function () {

    // get all the images (excluding those with no src attribute)
    var $imgs = this.find('img[src!=""]');
    // if there's no images, just return an already resolved promise
    if (!$imgs.length) {return $.Deferred().resolve().promise();}

    // for each image, add a deferred object to the array which resolves when the image is loaded (or if loading fails)
    var dfds = [];  
    $imgs.each(function(){

        var dfd = $.Deferred();
        dfds.push(dfd);
        var img = new Image();
        img.onload = function(){dfd.resolve();}
        img.onerror = function(){dfd.resolve();}
        img.src = this.src;

    });

    // return a master promise object which will resolve when all the deferred objects have resolved
    // IE - when all the images are loaded
    return $.when.apply($,dfds);

}

Then you can use it something like this:

$.ajax({
    cache: false,
    url: 'ajax/content.php',
    success: function(data) {
        $('#divajax').html(data).imagesLoaded().then(function(){
            // do stuff after images are loaded here
        });
    }
});

Hopefully that's helpful for someone.

Note that using the above code, if one of the images errors (eg because the URL was wrong), the promise is resolved anyway and the error is ignored. This might be what you want, but, depending on your situation, you might instead want to abort whatever you are doing if an image fails to load. In which case you could replace the onerror line as follows:

img.onerror = function(){dfd.reject();}

And catch the error like this:

$('#divajax').html(data).imagesLoaded().done(function(){
    // do stuff after all images are loaded successfully here
}).fail(function(){
    // do stuff if any one of the images fails to load
});