jQuery validate before ajaxForm

superUntitled picture superUntitled · Mar 8, 2010 · Viewed 11.4k times · Source

I am trying to use the "beforeSubmit" option in the jQuery ajaxForm plugin to validate the data, however the form will submit even if there are invalid form fields. Where have I gone wrong? thanks,

$(document).ready(function() { 
function validator(){ 
        $("#commentForm").validate();
}

    $('#commentForm').ajaxForm({ 
        dataType: 'json',
        url: "http://highlandfamilyeyecare.com/contactengine.php",
        beforeSubmit:  validator,
        success:        function(data) { 
            $('ul.form').fadeOut("slow");
            $('ul.form').html(data.formula).slideDown('slow');}
    });
});

And the html:

<ul class="form">


    <li>    
        <form method="post" action="form.php" id="commentForm">

        <label class="white">Your Name</label>
        <input class="text-input required" type="text" name="name" /></li>

    <li>
        <label class="white">Email</label>
        <input class="text-input required email" type="text" name="email"/></li>

    <li>
        <li><input type='submit' value="Submit" />
        </form></li>

</ul>

Answer

CWF picture CWF · Mar 8, 2010

The beforeSubmit() function isn't returning anything.

You'll want:

function validator() { 
  return $("#commentForm").validate();
}

presuming that the $('#commentForm").validate() exists and returns true/false correctly.