I'm trying to capture audiorecorder (https://github.com/cwilso/AudioRecorder) and send the blob through Ajax a php file, which will receive the blob content and create the file(the wave file in this case).
Ajax call:
audioRecorder.exportWAV(function(blob) {
var url = (window.URL || window.webkitURL).createObjectURL(blob);
console.log(url);
var filename = <?php echo $filename;?>;
$.ajaxFileUpload({
url : "lib/vocal_render.php",
secureuri :false,
dataType : blob.type,
data: blob,
success: function(data, status) {
if(data.status != 'error')
alert("boa!");
}
});
});
and my php file (vocal_render.php):
<?php
if(!empty($_POST)){
$data = implode($_POST); //transforms the char array with the blob url to a string
$fname = "11" . ".wav";
$file = fopen("../ext/wav/testes/" .$fname, 'w');
fwrite($file, $data);
fclose($file);
}?>
P.S:I'm newbie with blobs and ajax. Thanks in advance.
Try uploading the file as form data
audioRecorder.exportWAV(function(blob) {
var url = (window.URL || window.webkitURL).createObjectURL(blob);
console.log(url);
var filename = <?php echo $filename;?>;
var data = new FormData();
data.append('file', blob);
$.ajax({
url : "lib/vocal_render.php",
type: 'POST',
data: data,
contentType: false,
processData: false,
success: function(data) {
alert("boa!");
},
error: function() {
alert("not so boa!");
}
});
});
.
<?php
if(isset($_FILES['file']) and !$_FILES['file']['error']){
$fname = "11" . ".wav";
move_uploaded_file($_FILES['file']['tmp_name'], "../ext/wav/testes/" . $fname);
}
?>