jQuery UI Slider - Value returned from 'slide' event on release is different from 'change' value

wyqydsyq picture wyqydsyq · Feb 2, 2012 · Viewed 17.1k times · Source

I have a jQuery UI slider:

$('div.slider').slider({
    range: true,
    step: 250,
    min: 1000,
    max: 500000,
    values: [1000,500000],
    change: function(event, ui){
        console.log($(this).slider('values', 0)+','+$(this).slider('values', 1));
    },
    slide: function(event, ui){
        console.log($(this).slider('values', 0)+','+$(this).slider('values', 1));
    }
});

For some odd reason, when releasing the slider (mouseup) the value changes slightly from what it was. The slide event is returning something different than what the change event is. Anyone have any ideas what might be causing this and how I could solve it?

I'm going to have a pretty intense operation in the callback for the change event (meaning I can't just use sldie), but also need to show the values of the slider live, so I can't use just one or the other.

Here's a fiddle with this oddity in action: http://jsfiddle.net/5W6Zh/

Thanks in advance

Answer

Dan Hixon picture Dan Hixon · Aug 17, 2012

we ran into this tonight (and last night, and for the past few months). What we did to fix it was use ui.value and ui.values[0] instead of $("#slider").slider('values',0).

Use this:

change: function(event, ui) {
  $('.values').text(ui.values[0] + ',' + ui.values[1]);
}

Instead of:

change: function(event, ui) {
  $('.values').text($(this).slider('values', 0) + ',' + $(this).slider('values', 1));
}

I forked your jsfiddle and made it work: http://jsfiddle.net/danhixon/9JdhU/1/

Honestly I don't think I would have found the solution without your question and jsfiddle - I kept comparing it to the jquery-ui demo until I found this difference.