How to pass the value 'undefined' to a function with multiple parameters?

javascript function parameter-passing undefined
ajax333221 picture ajax333221 · Jan 25, 2012 · Viewed 51.4k times · Source

I want to pass the value of 'undefined' on a multiple parameter function but without omitting the parameter.

What do I mean with "without omitting the parameter". I mean that we should not just omit the parm2 like this example:

function myFunction (parm1, parm2) {}
myFunction("abc");

This will indeed make parm2 undefined, but I am not allowed to do it this way because I will need to specify other parameters AFTER the omitted parameter, so the previous method won't work in the case I want to make parm1 undefined BUT also want to have other parameters after this one to hold a value.

I have tried solving the problem with:

myFunction( ,"abc"); //doesn't seem to work

Update:

and myFunction(undefined, "abc");

Answer

xdazz picture xdazz · Jan 25, 2012

myFunction(undefined,"abc"); this way should work, what is the problem?

see here

Here is undefined documentation from mozilla, supported by all browsers

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