Array justPrices has values such as:
[0] = 1.5
[1] = 4.5
[2] = 9.9.
How do I return the smallest value in the array?
The tersest expressive code to find the minimum value is probably rest parameters:
const arr = [14, 58, 20, 77, 66, 82, 42, 67, 42, 4]
const min = Math.min(...arr)
console.log(min)
Rest parameters are essentially a convenient shorthand for Function.prototype.apply
when you don't need to change the function's context:
var arr = [14, 58, 20, 77, 66, 82, 42, 67, 42, 4]
var min = Math.min.apply(Math, arr)
console.log(min)
This is also a great use case for Array.prototype.reduce
:
const arr = [14, 58, 20, 77, 66, 82, 42, 67, 42, 4]
const min = arr.reduce((a, b) => Math.min(a, b))
console.log(min)
It may be tempting to pass Math.min
directly to reduce
, however the callback receives additional parameters:
callback (accumulator, currentValue, currentIndex, array)
In this particular case it may be a bit verbose. reduce
is particularly useful when you have a collection of complex data that you want to aggregate into a single value:
const arr = [{name: 'Location 1', distance: 14}, {name: 'Location 2', distance: 58}, {name: 'Location 3', distance: 20}, {name: 'Location 4', distance: 77}, {name: 'Location 5', distance: 66}, {name: 'Location 6', distance: 82}, {name: 'Location 7', distance: 42}, {name: 'Location 8', distance: 67}, {name: 'Location 9', distance: 42}, {name: 'Location 10', distance: 4}]
const closest = arr.reduce(
(acc, loc) =>
acc.distance < loc.distance
? acc
: loc
)
console.log(closest)
And of course you can always use classic iteration:
var arr,
i,
l,
min
arr = [14, 58, 20, 77, 66, 82, 42, 67, 42, 4]
min = Number.POSITIVE_INFINITY
for (i = 0, l = arr.length; i < l; i++) {
min = Math.min(min, arr[i])
}
console.log(min)
...but even classic iteration can get a modern makeover:
const arr = [14, 58, 20, 77, 66, 82, 42, 67, 42, 4]
let min = Number.POSITIVE_INFINITY
for (const value of arr) {
min = Math.min(min, value)
}
console.log(min)