Trying to figure out how to use the Jquery .on() method with a specific selector that has multiple events associated with it. I was previously using the .live() method, but not quite sure how to accomplish the same feat with .on(). Please see my code below:
$("table.planning_grid td").live({
mouseenter:function(){
$(this).parent("tr").find("a.delete").show();
},
mouseleave:function(){
$(this).parent("tr").find("a.delete").hide();
},
click:function(){
//do something else.
}
});
I know I can assign the multiple events by calling:
$("table.planning_grid td").on({
mouseenter:function(){ //see above
},
mouseleave:function(){ //see above
}
click:function(){ //etc
}
});
But I believe the proper use of .on() would be like so:
$("table.planning_grid").on('mouseenter','td',function(){});
Is there a way to accomplish this? Or what is the best practice here? I tried the code below, but no dice.
$("table.planning_grid").on('td',{
mouseenter: function(){ /* event1 */ },
mouseleave: function(){ /* event2 */ },
click: function(){ /* event3 */ }
});
Thanks in advance!
That's the other way around. You should write:
$("table.planning_grid").on({
mouseenter: function() {
// Handle mouseenter...
},
mouseleave: function() {
// Handle mouseleave...
},
click: function() {
// Handle click...
}
}, "td");