Detect iOS version less than 5 with JavaScript

Question

This is related to the "fix" for position:fixed in older versions of iOS. However, if iOS5 or greater is installed, the fix breaks the page.

I know how to detect iOS 5: navigator.userAgent.match(/OS 5_\d like Mac OS X/i) but that won't work for iOS6 when it eventually comes around, or even iOS 5.0.1, only a 2 digit version.

So this is what I have atm.

$(document).bind("scroll", function() {
    if((navigator.userAgent.match(/iPhone/i)) || (navigator.userAgent.match(/iPod/i)) || (navigator.userAgent.match(/iPad/i))) {
        if (navigator.userAgent.match(/OS 5_\d like Mac OS X/i)) {
    }
    else {
        changeFooterPosition();
    }
});

Answer 1

This snippet of code can be used to determine any version of iOS 2.0 and later.

function iOSversion() {
  if (/iP(hone|od|ad)/.test(navigator.platform)) {
    // supports iOS 2.0 and later: <http://bit.ly/TJjs1V>
    var v = (navigator.appVersion).match(/OS (\d+)_(\d+)_?(\d+)?/);
    return [parseInt(v[1], 10), parseInt(v[2], 10), parseInt(v[3] || 0, 10)];
  }
}

ver = iOSversion();

if (ver[0] >= 5) {
  alert('This is running iOS 5 or later.');
}