How to pass a callback as a parameter into another function

Wee Kiat picture Wee Kiat · Jun 24, 2011 · Viewed 118.9k times · Source

I'm new to ajax and callback functions, please forgive me if i get the concepts all wrong.

Problem: Could i send a callbackfunction as a parameter to another function that will execute the callback?

function firstFunction(){
    //some code

    //a callback function is written for $.post() to execute
    secondFunction("var1","var2",callbackfunction);
}

function secondFunction(var1, var2, callbackfunction) {
    params={}
    if (event != null) params = event + '&' + $(form).serialize();

    // $.post() will execute the callback function
    $.post(form.action,params, callbackfunction);
}

Answer

T.J. Crowder picture T.J. Crowder · Jun 24, 2011

Yup. Function references are just like any other object reference, you can pass them around to your heart's content.

Here's a more concrete example:

function foo() {
    console.log("Hello from foo!");
}

function caller(f) {
    // Call the given function
    f();
}

function indirectCaller(f) {
    // Call `caller`, who will in turn call `f`
    caller(f);
}

// Do it
indirectCaller(foo); // alerts "Hello from foo!"

You can also pass in arguments for foo:

function foo(a, b) {
    console.log(a + " + " + b + " = " + (a + b));
}

function caller(f, v1, v2) {
    // Call the given function
    f(v1, v2);
}

function indirectCaller(f, v1, v2) {
    // Call `caller`, who will in turn call `f`
    caller(f, v1, v2);
}

// Do it
indirectCaller(foo, 1, 2); // alerts "1 + 2 = 3"