Assuming an array of objects as follows:
const listOfTags = [
{id: 1, label: "Hello", color: "red", sorting: 0},
{id: 2, label: "World", color: "green", sorting: 1},
{id: 3, label: "Hello", color: "blue", sorting: 4},
{id: 4, label: "Sunshine", color: "yellow", sorting: 5},
{id: 5, label: "Hello", color: "red", sorting: 6},
]
A duplicate entry would be if label and color are the same. In this case Objects with id = 1 and id = 5 are duplicates.
How can I filter this array and remove duplicates?
I know solutions where you can filter against one key with something like:
const unique = [... new Set(listOfTags.map(tag => tag.label)]
But what about multiple keys?
As per request in comment, here the desired result:
[
{id: 1, label: "Hello", color: "red", sorting: 0},
{id: 2, label: "World", color: "green", sorting: 1},
{id: 3, label: "Hello", color: "blue", sorting: 4},
{id: 4, label: "Sunshine", color: "yellow", sorting: 5},
]
You could use a Set
in a closure for filtering.
const
listOfTags = [{ id: 1, label: "Hello", color: "red", sorting: 0 }, { id: 2, label: "World", color: "green", sorting: 1 }, { id: 3, label: "Hello", color: "blue", sorting: 4 }, { id: 4, label: "Sunshine", color: "yellow", sorting: 5 }, { id: 5, label: "Hello", color: "red", sorting: 6 }],
keys = ['label', 'color'],
filtered = listOfTags.filter(
(s => o =>
(k => !s.has(k) && s.add(k))
(keys.map(k => o[k]).join('|'))
)
(new Set)
);
console.log(filtered);
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