js override console.log if not defined

Radu Maris picture Radu Maris · Sep 22, 2010 · Viewed 30.7k times · Source

Which solution do you recommend, the second is simpler ( less code ), but there are drawbacks on using it ?

First: (Set a global debug flag)

// the first line of code
var debug = true;
try {
    console.log
} catch(e) {
    if(e) {
        debug=false;
    }
};
// Then later in the code
if(debug) {
    console.log(something);
}

Second: override console.log

try {
    console.log
} catch(e) {
    if (e) {
        console.log = function() {}
    }
};
// And all you need to do in the code is
console.log(something);

Answer

Andy E picture Andy E · Sep 22, 2010

Neither, but a variation of the second. Lose the try...catch and check for existence of the console object properly:

if (typeof console == "undefined") {
    window.console = {
        log: function () {}
    };
}

console.log("whatever");