Transition to another route on successful async redux action

Question

I have a pretty simple set of react components:

• container that hooks into redux and handles the actions, store subscriptions, etc
• list which displays a list of my items
• new which is a form to add a new item to the list

I have some react-router routes as follows:

<Route name='products' path='products' handler={ProductsContainer}>
  <Route name='productNew' path='new' handler={ProductNew} />
  <DefaultRoute handler={ProductsList} />
</Route>

so that either the list or the form are shown but not both.

What I'd like to do is to have the application re-route back to the list once a new item has been successfully added.

My solution so far is to have a .then() after the async dispatch:

dispatch(actions.addProduct(product)
  .then(this.transitionTo('products'))
)

Is this the correct way to do this or should I fire another action somehow to trigger the route change?

Answer 1

If you don't want to use a more complete solution like Redux Router, you can use Redux History Transitions which lets you write code like this:

export function login() {
  return {
    type: LOGGED_IN,
    payload: {
      userId: 123
    }
    meta: {
      transition: (state, action) => ({
        path: `/logged-in/${action.payload.userId}`,
        query: {
          some: 'queryParam'
        },
        state: {
          some: 'state'
        }
      })
    }
  };
}

This is similar to what you suggested but a tiny bit more sophisticated. It still uses the same history library under the hood so it's compatible with React Router.