Show loading gif after clicking form submit using jQuery

ValleyDigital picture ValleyDigital · Nov 19, 2014 · Viewed 106.8k times · Source

I'm trying to simply show a loading gif once the form is submitted. My code is not working correctly for the loading gif to show. You'll see my image for the gif is set to visibility: hidden.

<script src="js/jquery-1.11.1.min.js"></script>

<div class="" style="width: 480px; margin: 0 auto; margin-top: 20px;" id="form_wrapper">
    <img src="img/loader.gif" id="gif" style="display: block; margin: 0 auto; width: 100px; visibility: hidden;">
    <div class="fade" id="form">
        <form action="process_login.php" method="POST" name="simplelogin" id="login_form"><br />
            <label for="username">&nbsp; Username:</label>
            <input type="username" name="username" id="username" size="30" required><br><br>
            <label for="password">&nbsp; Password:</label>
            <input type="password" name="password" id="password" size="30" required><br><br>
            <input class="load_button" type="submit" name="submit" id="submit" value="Submit" placeholder="Submit">
        </form>
    </div>
</div>
<div class="fifty"></div>

<script type="text/javascript">
    $('.load_button').submit(function() {
        $('#gif').show(); 
        return true;
    });
</script>

Answer

Rory McCrossan picture Rory McCrossan · Nov 19, 2014

The show() method only affects the display CSS setting. If you want to set the visibility you need to do it directly. Also, the .load_button element is a button and does not raise a submit event. You would need to change your selector to the form for that to work:

$('#login_form').submit(function() {
    $('#gif').css('visibility', 'visible');
});

Also note that return true; is redundant in your logic, so it can be removed.