How to build minified and uncompressed bundle with webpack?

Thank you picture Thank you · Sep 21, 2014 · Viewed 220.1k times · Source

Here's my webpack.config.js

var webpack = require("webpack");

module.exports = {

  entry: "./entry.js",
  devtool: "source-map",
  output: {
    path: "./dist",
    filename: "bundle.min.js"
  },
  plugins: [
    new webpack.optimize.UglifyJsPlugin({minimize: true})
  ]
};

I'm building with

$ webpack

In my dist folder, I'm only getting

  • bundle.min.js
  • bundle.min.js.map

I'd also like to see the uncompressed bundle.js

Answer

lyosef picture lyosef · Jul 5, 2015

You can use a single config file, and include the UglifyJS plugin conditionally using an environment variable:

const webpack = require('webpack');
const TerserPlugin = require('terser-webpack-plugin');

const PROD = JSON.parse(process.env.PROD_ENV || '0');

module.exports = {

  entry: './entry.js',
  devtool: 'source-map',
  output: {
    path: './dist',
    filename: PROD ? 'bundle.min.js' : 'bundle.js'
  },
  optimization: {
    minimize: PROD,
    minimizer: [
      new TerserPlugin({ parallel: true })
  ]
};

and then just set this variable when you want to minify it:

$ PROD_ENV=1 webpack

Edit:

As mentioned in the comments, NODE_ENV is generally used (by convention) to state whether a particular environment is a production or a development environment. To check it, you can also set const PROD = (process.env.NODE_ENV === 'production'), and continue normally.