Is there a clean way to remove undefined fields from an object?
i.e.
> var obj = { a: 1, b: undefined, c: 3 }
> removeUndefined(obj)
{ a: 1, c: 3 }
I came across two solutions:
_.each(query, function removeUndefined(value, key) {
if (_.isUndefined(value)) {
delete query[key];
}
});
or:
_.omit(obj, _.filter(_.keys(obj), function(key) { return _.isUndefined(obj[key]) }))
A one-liner using ES6 arrow function and ternary operator:
Object.keys(obj).forEach(key => obj[key] === undefined ? delete obj[key] : {});
Or use short-circuit evaluation instead of ternary: (@Matt Langlois, thanks for the info!)
Object.keys(obj).forEach(key => obj[key] === undefined && delete obj[key])
Same example using if expression:
Object.keys(obj).forEach(key => {
if (obj[key] === undefined) {
delete obj[key];
}
});
If you want to remove the items from nested objects as well, you can use a recursive function:
const removeEmpty = (obj) => {
Object.keys(obj).forEach(key => {
if (obj[key] && typeof obj[key] === 'object') removeEmpty(obj[key]);
else if (obj[key] === undefined) delete obj[key];
});
return obj;
};