I am a total noob, so please go easy.
I am trying to replace one image with a second image while hovering on a different element. My problem is that only the first image is being replaced by the link images. I've give each image an ID, I just am not sure how to apply it.
Thank you in advance for any help you can provide!
Here is what I have so far:
Script:
<script>
function changeimage(towhat,url){
if (document.images){
document.images.targetimage.src=towhat.src
gotolink=url
}
}
function warp(){
window.location=gotolink
}
</script>
<script language="JavaScript1.1">
var myimages=new Array()
var gotolink="#"
function preloadimages(){
for (i=0;i<preloadimages.arguments.length;i++){
myimages[i]=new Image()
myimages[i].src=preloadimages.arguments[i]
}
}
preloadimages("http://www.dxmgp.com/group/images/color_si.jpg", "http://www.dxmgp.com/group/images/bw_si.jpg","http://www.dxmgp.com/group/images/color_dxm.jpg", "http://www.dxmgp.com/group/images/bw_dxm.jpg","http://www.dxmgp.com/group/images/color_tsg.jpg", "http://www.dxmgp.com/group/images/bw_tsg.jpg","http://www.dxmgp.com/group/images/color_image.jpg", "http://www.dxmgp.com/group/images/bw_image.jpg")
</script>
HTML:
<div id="wrap">
<div id="upper">
<div class="u-top">
<a href="javascript:warp()"><img src="http://www.dxmgp.com/group/images/bw_si.jpg" name="targetimage" id="si" border="0" /></a>
<a href="javascript:warp()"><img class="picright" src="http://www.dxmgp.com/group/images/bw_dxm.jpg" name="targetimage" id="dxm" border="0" /></a>
</div>
<div class="u-mid">
<img src="http://www.dxmgp.com/group/images/bw_owners.png" />
</div>
<div class="u-low">
<a href="javascript:warp()"><img class="picleft" src="http://www.dxmgp.com/group/images/bw_tsg.jpg" id="tsg" /></a>
<a href="http://www.dxmgp.com" onMouseover="changeimage(myimages[2],this.href)" onMouseout="changeimage(myimages[3],this.href)"><img class="dxmlogo" src="http://www.dxmgp.com/group/images/logo_dxm.png" /></a>
<a href="javascript:warp()"><img class="picright" src="http://www.dxmgp.com/group/images/bw_image.jpg" id="img" /></a>
</div>
</div>
<div id="lower">
<div class="dots"><img src="http://www.dxmgp.com/group/images/topdots.png"></div>
<div class="logos">
<a href="http://www.thescoutguide.com">
<img class="picll" src="http://www.dxmgp.com/group/images/logo_tsg.png"></a>
<a href="http://www.spatialinsights.com" onMouseover="changeimage(myimages[0],this.href)" onMouseout="changeimage(myimages[1],this.href)"><img class="picmid" src="http://www.dxmgp.com/group/images/logo_si.png"></a>
<a href="http://www.imagebydxm.com">
<img class="piclr" src="http://www.dxmgp.com/group/images/logo_image.png"></a>
</div>
<div class="dots"><img src="http://www.dxmgp.com/group/images/lowdots.png"></div>
</div>
</div>
How about something like this? Consider you have a div
containing image1.png
. When you mouse over a hyperlink, you want to replace image1.png
with image2.png
. Then, when you move your mouse away from the hyperlink, image2.png
will once again be replaced with image1.png
:
This is your div
containing the image:
<div id="image">
<img src="image1.png" />
</div>
This is the hyperlink:
<a href="#" onmouseover="mouseOver()" onmouseout="mouseOut()">Mouse over to change image</a>
Here are the JavaScript functions that will replace the inner HTML of the div
with different images:
<script type="text/javascript">
function mouseOver() {
document.getElementById("image").innerHTML = '<img src="image2.png" />';
}
function mouseOut() {
document.getElementById("image").innerHTML = '<img src="image1.png" />';
}
</script>
Let me know if this is what you are looking for.