I've got an array of arrays, something like:
[
[1,2,3],
[1,2,3],
[1,2,3],
]
I would like to transpose it to get the following array:
[
[1,1,1],
[2,2,2],
[3,3,3],
]
It's not difficult to programmatically do so using loops:
function transposeArray(array, arrayLength){
var newArray = [];
for(var i = 0; i < array.length; i++){
newArray.push([]);
};
for(var i = 0; i < array.length; i++){
for(var j = 0; j < arrayLength; j++){
newArray[j].push(array[i][j]);
};
};
return newArray;
}
This, however, seems bulky, and I feel like there should be an easier way to do it. Is there?
array[0].map((_, colIndex) => array.map(row => row[colIndex]));
map
calls a providedcallback
function once for each element in an array, in order, and constructs a new array from the results.callback
is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values.
callback
is invoked with three arguments: the value of the element, the index of the element, and the Array object being traversed. [source]