CSS3: How to rotate and scale an img at the same time?

Question

I'm very confused. Why can't I use scale and rotate at the same time? I've tried this, but it does not work:

.rotate-img{
    -webkit-transform:scale(2,2);
    -webkit-transform:rotate(90deg);
    margin-left:20%;
    margin-top:10%;
}

I tried jQuery, but does not work neither:

<style>
.zoom{
        -webkit-transform:scale(2,2);
        margin-left:20%;
        margin-top:10%;
    }
</style>
<script>

    $(document).ready(function(){
        $("img").dblclick(function(){

            $(this).addClass("zoom");

            $(this).contextmenu(function(){
                $(this).css("-webkit-transform","rotate(90deg)");
                return false;
            })
        });
    })

    </script>

How could I scale an img and when I clic the right click then rotate 90 deg.

Answer 1

You can rotate an image with CSS using the transform property with a rotate(**deg) value

.rotate-img {
    -webkit-transform : rotate(90deg) scale(0.2); /* Chrome, Opera 15+, Safari 3.1+ */
    -ms-transform     : rotate(90deg) scale(0.2); /* IE 9 */
    transform         : rotate(90deg) scale(0.2); /* Firefox 16+, IE 10+, Opera */
    left : -200px;
    position: relative;
}

<img class="rotate-img" src="https://appharbor.com/assets/images/stackoverflow-logo.png" />

When applying transform on multiple lines, it's like any other CSS property, and it gets overwritten so only the last line is used, just like with something like :

.myclass {
    top: 100px;
    top: 400px;
}

only the last one would apply, so you'll need to put all the transformations in one transform.