When passing the following code to jshint, it considers the linebreak in the if-condition to be bad, saying "Bad line breaking before '&&'."
if (1 == 1
&& true) {
console.log("hello world");
}
However, having the linebreak after '&&' is fine.
if (1 == 1 &&
true) {
console.log("hello world");
}
Why does jshint consider the first to be wrong and the latter to be right?
According to a discussion on GitHub:
This may cause problems like semi colon insertion and old javascript parsers breaking. Please check a large range of browsers.
This check can be disabled with .laxbreak:true
The laxbreak
option is on its way to deprecation, but I'm not sure if the default jshint behavior will change.