I am using the Tooltips provided by Twitter Bootstrap (http://twitter.github.com/bootstrap/javascript.html#tooltips).
I have some dynamically inserted markup in my DOM which needs to trigger the tooltips. That's why I trigger tooltips in the following way (https://github.com/twitter/bootstrap/issues/4215):
$('body').tooltip({
delay: { show: 300, hide: 0 },
selector: '[rel=tooltip]:not([disabled])'
});
To avoid tooltips being placed too close to the edge of the screen, I need to be able to set their position dynamically based on where the element which triggers the tooltip is positioned. I thought of doing it the following way:
$('body').tooltip({
delay: { show: 300, hide: 0 },
// here comes the problem...
placement: positionTooltip(this),
selector: '[rel=tooltip]:not([disabled])'
});
function positionTooltip(currentElement) {
var position = $(currentElement).position();
if (position.left > 515) {
return "left";
}
if (position.left < 515) {
return "right";
}
if (position.top < 110){
return "bottom";
}
return "top";
}
How can I pass currentElement correctly to the positionTooltip function in order to return the appropriate placement value for each tooltip?
Thanks in advance
Bootstrap calls the placement function with params that includes the element
this.options.placement.call(this, $tip[0], this.$element[0])
so in your case, do this :
$('body').tooltip({
delay: { show: 300, hide: 0 },
placement: function(tip, element) { //$this is implicit
var position = $(element).position();
if (position.left > 515) {
return "left";
}
if (position.left < 515) {
return "right";
}
if (position.top < 110){
return "bottom";
}
return "top";
},
selector: '[rel=tooltip]:not([disabled])'
});