I'm trying to figure out how to clone an Ext.data.Store
without keeping the old reference.
Let me explain better with some code. Here's the source store:
var source = Ext.create ('Ext.data.Store', {
fields: ['name', 'age'] ,
data: [
{name: 'foo', age: 20} ,
{name: 'boo', age: 30} ,
{name: 'too', age: 10} ,
{name: 'yoo', age: 80} ,
{name: 'zoo', age: 30}
]
});
Follows an example of what I want to do:
var target = source;
target.removeAll ();
// Here I need to have target empty and source unchanged
// But in this case, source is empty as well
Now, in the above example the copy is done by reference while I need to do it by value.
So I found Ext.clone ()
in the docs but it seems it doesn't work for complex object, like Ext.data.Store
:
var target = Ext.clone (source);
target.removeAll ();
// source is still empty
Then I tried with Ext.data.Model.copy ()
but the only way to do it work is this:
var target = Ext.create ('Ext.data.Store', {
fields: ['name', 'age']
});
source.each (function (model) {
target.add (model.copy ());
});
Now, for my reasons, I don't want to instantiate another Ext.data.Store
, so I want to avoid this:
var target = Ext.create ('Ext.data.Store', {
fields: ['name', 'age']
});
I'd like to have something like this:
var target;
source.each (function (model) {
target.add (model.copy ());
});
But, obviously, it doesn't work.
So, how can I clone the source store?
ExtJS 6.x, 5.x and 4.x solution
Here's a quasi-all ExtJS versions solution. Mind you that record.copy already creates a clone of the data. No need to Ext.clone that again.
function deepCloneStore (source) {
source = Ext.isString(source) ? Ext.data.StoreManager.lookup(source) : source;
var target = Ext.create(source.$className, {
model: source.model,
});
target.add(Ext.Array.map(source.getRange(), function (record) {
return record.copy();
}));
return target;
}