So I have the submit button that looks like this:
<a href="#" id="submitbutton"
onClick="document.getElementById('UploaderSWF').submit();">
<img src="../images/user/create-product.png" border="0" /></a>
When I double click it double submits obviously, and the problem is that I'm saving the information in the database so I'll have dublicate information there, and I dont want that. This uploader uses flash and javscript and here is a little piece of code that is relevant to the submit thing (if it helps)
$.fn.agileUploaderSubmit = function() {
if($.browser.msie && $.browser.version == '6.0') {
window.document.agileUploaderSWF.submit();
} else {
document.getElementById('agileUploaderSWF').submit();
return false;
}
}
Thank you guys. I appreciate your help. This is really something I was unable to do myself because I have such a little experience with js and I dont really know how to do stuff. THANKS.
Try this snipped:
$('#your_submit_id').click(function(){
$(this).attr('disabled');
});
edit 1
Oh, in your case it is a link and no submit button ...
var submitted = false;
$.fn.agileUploaderSubmit = function() {
if ( false == submitted )
{
submitted = true;
if($.browser.msie && $.browser.version == '6.0') {
window.document.agileUploaderSWF.submit();
} else {
document.getElementById('agileUploaderSWF').submit();
}
}
return false;
}
edit 2
To simplify this, try this:
<!doctype html>
<html dir="ltr" lang="en">
<head>
<meta charset="utf-8" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript">
<!--//--><![CDATA[//><!--
$(document).ready(function()
{
$('#yourSubmitId').click(function()
{
$(this).attr('disabled',true);
/* your submit stuff here */
return false;
});
});
//--><!]]>
</script>
</head>
<body>
<form id="yourFormId" name="yourFormId" method="post" action="#">
<input type="image" id="yourSubmitId" name="yourSubmitId" src="yourImage.png" alt="Submit" />
</form>
</body>
</html>
Use form elements, like <input type="image" />
, to submit a form not a normal link.
This works fine!
Take a look at jQuery.post() to submit your form.
Good luck.
edit 3
This works well for me too:
<!doctype html>
<html dir="ltr" lang="en">
<head>
<meta charset="utf-8" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript">
<!--//--><![CDATA[//><!--
$(document).ready(function()
{
var agileUploaderSWFsubmitted = false;
$('#submitbutton').click(function()
{
if ( false == agileUploaderSWFsubmitted )
{
agileUploaderSWFsubmitted = true;
//console.log( 'click event triggered' );
if ( $.browser.msie && $.browser.version == '6.0' )
{
window.document.agileUploaderSWF.submit();
}
else
{
document.getElementById( 'agileUploaderSWF' ).submit();
}
}
return false;
});
});
//--><!]]>
</script>
</head>
<body>
<form id="agileUploaderSWF" name="agileUploaderSWF" method="post" action="http://your.action/script.php">
<input type="text" id="agileUploaderSWF_text" name="agileUploaderSWF_text" />
</form>
<a href="#" id="submitbutton"><img src="../images/user/create-product.png" border="0" /></a>
</body>
</html>
Hopefully this helps.