In my course, I am told:
Continuous values are represented approximately in memory, and therefore computing with floats involves rounding errors. These are tiny discrepancies in bit patterns; thus the test
e==f
is unsafe ife
andf
are floats.
Referring to Java.
Is this true? I've used comparison statements with double
s and float
s and have never had rounding issues. Never have I read in a textbook something similar. Surely the virtual machine accounts for this?
It is true.
It is an inherent limitation of how floating point values are represented in memory in a finite number of bits.
This program, for instance, prints "false":
public class Main {
public static void main(String[] args) {
double a = 0.7;
double b = 0.9;
double x = a + 0.1;
double y = b - 0.1;
System.out.println(x == y);
}
}
Instead of exact comparison with '==' you usually decide on some level of precision and ask if the numbers are "close enough":
System.out.println(Math.abs(x - y) < 0.0001);