I was writing some code for an interviewstreet.com challenge My code gives a NumberFormatException
import java.io.*;
public class BlindPassenger
{
public static void main(String [] args) throws IOException
{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String line = br.readLine();
int t,n;
//System.out.println(line);
t = Integer.parseInt(line);
for(int i=0;i<t;++i)
{
line = br.readLine();
n = Integer.parseInt(line); --n;
if(n == 0)
{
System.out.println("poor conductor");
}
else
{
char direction='l',seat_posn='l';
int row_no = 0, relative_seat_no = 0;
row_no = (int) Math.ceil(n/5.0);
relative_seat_no = n % 5;
if(row_no % 2 == 0)
{
//even row, need to reverse the relative seat no
relative_seat_no = 6 - relative_seat_no;
}
if(relative_seat_no < 3)
{
direction = 'L';
if(relative_seat_no == 1) seat_posn = 'W';
else seat_posn = 'A';
}
else
{
direction = 'R';
if(relative_seat_no == 3) seat_posn = 'A';
else if(relative_seat_no == 4) seat_posn = 'M';
else seat_posn = 'W';
}
System.out.println(row_no + " " + seat_posn + " " + direction);
}
}
}
}
Here is the test case that they use
3
1
2
3
Output:
poor conductor
1 W L
1 A L
There seems to be a trailing space or something at the end of each line that causes the exception.
$ java BlindPassenger <input00.txt
Exception in thread "main" java.lang.NumberFormatException: For input string: "3
"
at java.lang.NumberFormatException.forInputString(NumberFormatException.
java:65)
at java.lang.Integer.parseInt(Integer.java:492)
at java.lang.Integer.parseInt(Integer.java:527)
at BlindPassenger.main(BlindPassenger.java:11)
This has taken up half an hour and I don't know how to fix this. Kills the fun of the event doesn't it. Can someone tell me what I'm doing wrong.
Integer.parseInt()
can't handle strings that don't fit its expected format, as you've found out. You could trim()
the string before you parse it:
t = Integer.parseInt(line.trim());
This gets rid of leading and trailing whitespace.