Getting stacktrace in logger

JNPW picture JNPW · Feb 2, 2012 · Viewed 66.2k times · Source

I am using log4j to log my exceptions. I want to log whatever I get in e.printStackTrace();
My code looks like this:

try {

} catch(Exception e) {
    log.error("Exception is:::" + e);
}

But the content I get logged looks like this:

2012-02-02 12:47:03,227 ERROR [com.api.bg.sample] - Exception in unTech:::[Ljava.lang.StackTraceElement;@6ed322
2012-02-02 12:47:03,309 ERROR [com.api.bg.sample] - Exception is :::java.lang.IndexOutOfBoundsException: Index: 0, Size: 0

But the content I expect is:

java.io.IOException: Not in GZIP format
at java.util.zip.GZIPInputStream.readHeader(Unknown Source)
at java.util.zip.GZIPInputStream.<init>(Unknown Source)
at java.util.zip.GZIPInputStream.<init>(Unknown Source)
at com.api.bg.sample.unGZIP(sample.java:191)
at com.api.bg.sample.main(sample.java:69)

I tried e.getMessage(), e.getStackTrace(); however I don't get the full stacktrace. Any suggestions?

Answer

Brian Tarbox picture Brian Tarbox · Feb 2, 2012

You have to use the two argument form

log.error("my logging message", exception)

See http://www.devdaily.com/blog/post/java/how-print-exception-stack-trace-using-log4j-commons for more details.