I'm trying to do a linear order traversal on a binary tree but having trouble getting the correct output. Basically I have created a queue and start by enqueuing the root, then until the queue is empty I dequeue the first element and add its children to the end of the queue. When dequeuing it returns a generic element (). I have a problem in converting this element to a tree node so that I can enqueue its children to the end of the queue in the next step. Here's what I have done so far:
public void levelOrderTraversal()
{
NodeQueue<E> queue = new NodeQueue<E>();
BTPosition<E> current = root;
queue.enqueue(current.element());
E temp = null;
while(!queue.isEmpty())
{
temp = queue.dequeue();
System.out.println(temp.toString());
current.setElement(temp);
if (hasLeft(current))
{
queue.enqueue(left(current).element());
}
if (hasRight(current))
{
queue.enqueue(right(current).element());
}
}
}
API for BTPosition and NodeQueue can be found in http://net3.datastructures.net/doc4/index.html?net/datastructures/
Any suggestions are really appreciated..
You'll want the Queue to be of type BTPosition<E>
. <E>
is simply the object type, for instance Integer
or String
. BTPosition
appears to be the actual node in your binary tree.
public void levelOrderTraversal()
{
NodeQueue<BTPosition<E>> queue = new NodeQueue<BTPosition<E>>();
BTPosition<E> current = root;
queue.enqueue(current);
while(!queue.isEmpty())
{
current = queue.dequeue();
System.out.println(temp.element().toString());
if (current.getLeft() != null)
{
queue.enqueue(current.getLeft());
}
if (current.getRight() != null)
{
queue.enqueue(current.getRight());
}
}
}