How to test protected methods of abstract class using JUnit and JMock

Maciej Piechotka picture Maciej Piechotka · Dec 4, 2011 · Viewed 9k times · Source

I have such situation - I have interface (say MyInterface) and simple partial implementation (AbstractMyInterface). The latter adds a few protected methods which I would like to test.

Currently I simply write by hand a mock object which extends AbstractMyInterface and export protected methods as public. Is there a simpler way of doing this - for example using JMock+scripting?

Answer

Mikko Maunu picture Mikko Maunu · Dec 4, 2011

I cannot see any problem with testing protected methods with JUnit. As long as package structure for tests mirrors source tree structure, methods other than private are visible for tests.

Of course if implementation to test is abstract, you have to create normal subclass of class under test by yourself (or do it via some mocking library if fits better for your purposes). Also in such a case, no need to create layer of public methods for just for calling protected visibility methods. Only for private methods this strategy does not work. But often need to test private methods is sign of design problem anyway.

For example: Class to test located to src/mypackage/AbstractClass.java package mypackage;

/** This could as well implement some interface, 
    but that does not change a thing */
public abstract class AbstractClass {
    protected int returnsOne() {
        return 1;
    }
}

And test which is located to tests/mypackage/AbstractClassTest.java

package mypackage;

import org.junit.Test;

import static junit.framework.Assert.assertEquals;

public class AbstractClassTest {
    @Test
    public void returnsOneReturnsOne() {
        AbstractClass instanceToTest = new AbstractClassTestable();
        assertEquals(1, instanceToTest.returnsOne());
    }
}

/** This is needed, because we cannot construct abstract class directly */
class AbstractClassTestable extends AbstractClass {
}