Sorry if this has been asked before, but I couldn't find any answers on the web. I'm having a hard time figuring out the inverse to this regex:
"\"[^>]*\">"
I want to use replaceAll to replace everything except the link. So if I had a tag similar to this:
<p><a href="http://www.google.com">Google</a></p>
I need a regex that would satisfy this:
s.replaceAll(regex, "");
to give me this output:
http://www.google.com
I know there are better ways to do this, but I have to use a regex. Any help is really appreciated, thanks!
You do not have to use replaceAll
. Better use pattern groups like the following:
Pattern p = Pattern.compile("href=\"(.*?)\"");
Matcher m = p.matcher(html);
String url = null;
if (m.find()) {
url = m.group(1); // this variable should contain the link URL
}
If you have several links into your HTML perform m.find()
in loop.