Spring Integration: Content based router with default output channel?

Question

I'd like use Spring Integration to implement a content based router that uses a default output channel if the expression value doesn't match any of the mappings. Here's my bean definition:

<int:router input-channel="channel_in" default-output-channel="channel_default" expression="payload.name">
    <int:mapping value="foo" channel="channel_one" />
    <int:mapping value="bar" channel="channel_two" />

However, it seems the default output channel is never used. If the expression evaluates to e.g. 'baz', the router seems to be looking for a channel named 'baz', instead of routing to the 'channel_default' channel:

org.springframework.integration.MessagingException: failed to resolve channel name 'baz'
  Caused by: org.springframework.integration.support.channel.ChannelResolutionException: 
    failed to look up MessageChannel bean with name 'baz'
  Caused by: org.springframework.beans.factory.NoSuchBeanDefinitionException: 
    No bean named 'baz' is defined

Is what I want at all possible using the XML namespace, or do I need to code up my own implementation?

Answer 1

Turns out that all I had to to to make this work was to set the router's ignore-channel-name-resolution-failures attribute to false:

<int:router input-channel="channel_in" default-output-channel="channel_default" 
  expression="payload.name" ignore-channel-name-resolution-failures="true">
    <int:mapping value="foo" channel="channel_one" />
    <int:mapping value="bar" channel="channel_two" />
</int:router>

I thought I had tried that before, but I seems I didn't.